Light of frequency `7.21xx10^(14)Hz` is incident on a metal surface. Electrons with a maximum speed of `6.0xx10^(5)ms^(-1)` are ejected from the surface. What is the threshold frequency for photoemission of electrons? `h=6.63xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg`.

Explanation

To find the threshold frequency for photoemission of electrons, we can use Einstein's photoelectric equation:

\[ E = h\nu = h\nu_0 + KE_{max} \]

Where:
- \( E \) is the energy of the incident photon,
- \( h \) is Planck's constant,
- \( \nu \) is the frequency of the incident light,
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