In an accelerator experiment on high energy collision of electrons with positrons, a certain events is interpreted as annihilation of an electron-positron pair of total energy 10.2 BeV into two `gamma`-rays of equal energy. What is the wavelength associated with each `gamma`-rays? `(1BeV=10^(9)eV)`

Explanation

To solve the problem of finding the wavelength associated with each gamma-ray produced from the annihilation of an electron-positron pair with a total energy of 10.2 BeV, we can follow these steps:

### Step 1: Convert Total Energy to Joules
The total energy (E) of the electron-positron pair is given as 10.2 BeV. We need to convert this energy into joules.

\[ E = 10.2 \, \text{BeV} = 10.2 \times 10^9 \, \text{eV} \]
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