What is the order of a reaction which has a rate expression rate = K[A]^(3//2)[B]^(-1)
The order of a reaction which has the rate expression (dc)/(dt) = k[E]^(3//2)[D]^(3//2) is
The order of a reaction with rate law, Rate= kC_A^(3//2) C_B^(1//2) will be:
For a reaction pA + qB rarr Product, the rate law expresison is r = k[A][B]^(m) . Then
For a reaction whose rate expression is rate (dx)/(dt)=k[A]^(1//2) [B]^(3//2) the overall order of the reaction will be:
The data for the reaction: A + B overset(k)rarr C . |{:("Experiment",[A]_(0),[B]_(0),"Initial rate"),(1,0.012,0.035,0.10),(2,0.024,0.070,0.80),(3,0.024,0.035,0.10),(4,0.012,0.070,0.80):}| The rate law corresponding to the above data is (a) Rate = k[B]^(3) , (b) Rate = k[B]^(4) ( c) Rate = k[A][B]^(3) , (d) Rate = k[A]^(2)[B]^(2)
The reaction A +3B to 2C obeys the rate equation Rate =k [A]^(1//2) [B]^(3//2) What is the order of the reaction ?
For a first order reaction, A rarr B , the rate = k xx…………. .
