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The initial concentration of N(2)O(5) in...

The initial concentration of `N_(2)O_(5)` in the following first order reaction:
`N_(2)O_(5)(g) rarr 2NO_(2)(g)+(1)/(2)O_(2)(g)`
was `1.24 xx 10^(-2) mol L^(-1)` at `318 K`. The concentration of `N_(2)O_(5)` after `60 min` was `0.20 xx 10^(-2) mol L^(-1)`. Calculate the rate constant of the reaction at `318 K`.

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AI Generated Solution

To calculate the rate constant \( k \) for the first-order reaction \( N_2O_5(g) \rightarrow 2NO_2(g) + \frac{1}{2}O_2(g) \), we can use the first-order rate equation: \[ k = \frac{2.303}{t} \log \left( \frac{[A_0]}{[A_t]} \right) \] where: - \( [A_0] \) is the initial concentration of \( N_2O_5 \) ...
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