For a reaction, `A+Brarr` Product, the rate law is given by `r=k[A]^((1)/(2))[B]^(2)`. What is the order of the reaction ?
Text Solution
AI Generated Solution
To determine the order of the reaction given the rate law \( r = k[A]^{\frac{1}{2}}[B]^{2} \), we will follow these steps:
### Step 1: Identify the rate law expression
The rate law expression is given as:
\[ r = k[A]^{\frac{1}{2}}[B]^{2} \]
### Step 2: Identify the exponents of the concentration terms
In the rate law:
...
Topper's Solved these Questions
CHEMICAL KINETICS
NCERT ENGLISH|Exercise Exercise|1 Videos
CHEMICAL KINETICS
NCERT ENGLISH|Exercise SOLVED EXAMPLE|1 Videos
BIOMOLECULES
NCERT ENGLISH|Exercise Exercise|33 Videos
CHEMISTRY IN EVERYDAY LIFE
NCERT ENGLISH|Exercise Exercise|32 Videos
Similar Questions
Explore conceptually related problems
(a) For a reaction , A+B rarr Product the rate law is given rate = k[A]^(1)[B]^(2) .What is the order of the reaction ? (b) write the unit of rate constant k for the first order reaction
(a) For a reaction ABrarrP , the rate law is given by, r=k[A]^(1//2)[B]^(2). What is the order of this reaction? (b) A first order reaction is found to have a rate constant k=5.5xx10^(-14)s^(-1) , Find the half life of the reaction.
For a reaction pA + qB rarr Product, the rate law expresison is r = k[A][B]^(m) . Then
The reaction A +3B to 2C obeys the rate equation Rate =k [A]^(1//2) [B]^(3//2) What is the order of the reaction ?
For a reaction A +B → C, the experimental rate law is found to be R=k[A]^1[B]^(1/2) . Find the rate of the reaction when [A] = 0.5 M, [B] = 0.1 M and k=0.03.
For a hypothetical reaction: A+B rarr Products, the rate law is r = k[A][B]^(0) . The order of reaction is
For a reaction A+ B to Products, the rate law is -Rate = k[A][B]^(3//2) Can the reaction be an elementray reaction ? Explain.
The rate of certain hypothetical reaction A+B+C rarr Products, is given by r = -(dA)/(dt) = k[A]^(1//2)[B]^(1//3)[C]^(1//4) The order of a reaction is given by