The decomposition of dimethyl ether leads to the formation of `CH_(4),H_(2),` and `CO` and the reaction rate is given by Rate `=k[CH_(3)OCH_(3)]^(3//2)` The rate of reaction is followed by increase in the pressure in a closed vessel , so the rate can also be expressed in terms of the partial pressure of dimethyl either, `i.e., ` Rate `=k[p_(CH_(3)OCH_(3))]^(3//2)` If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant ?
Text Solution
AI Generated Solution
To solve the problem, we need to determine the units of the rate and the rate constant for the given reaction involving the decomposition of dimethyl ether.
### Step 1: Determine the Units of Rate
The rate of a reaction is defined as the change in concentration (or pressure in this case) over time. The rate is given in terms of the partial pressure of dimethyl ether, which is expressed as:
\[
\text{Rate} = k [p_{\text{CH}_3\text{OCH}_3}]^{3/2}
\]
...
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