A reaction is second order with respect to a reaction. How is the rate of reaction affected if the (a) doubled, (b) reduced to `1//2`?
Text Solution
AI Generated Solution
To solve the problem, we need to analyze how the rate of a second-order reaction is affected by changes in the concentration of the reactant, A.
### Step-by-Step Solution:
1. **Understanding the Rate Law**:
For a second-order reaction with respect to reactant A, the rate law can be expressed as:
\[
\text{Rate} = k[A]^2
...
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