The rate constant for the decomposition of hydrocarbons is `2.418xx10^(-5)s^(-1)` at `546K`. If the energy of activation is `179.9kJ mol^(-1)`, what will be the value of pre`-`exponential factor?
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AI Generated Solution
To find the pre-exponential factor (A) for the decomposition of hydrocarbons, we can use the Arrhenius equation, which is given by:
\[ k = A e^{-\frac{E_a}{RT}} \]
Where:
- \( k \) is the rate constant,
- \( A \) is the pre-exponential factor,
- \( E_a \) is the energy of activation,
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