The rate constant for the first order decomposition of a certain reaction is described by the equation `log k (s^(-1)) = 14.34 - (1.25 xx 10^(4)K)/(T)` (a) What is the energy of activation for the reaction? (b) At what temperature will its half-life period be `256 min`?
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To solve the given problem, we will break it down into two parts as specified in the question.
### Part (a): Finding the Energy of Activation (Ea)
1. **Given Equation**:
The rate constant for the first-order decomposition is given by:
\[
\log k = 14.34 - \frac{1.25 \times 10^4 K}{T}
...
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