The resistance of a conductivity cell filled with `0.1 M KCl` solution is `100 Omega`. If `R` of the same cell when filled with `0.02 M KCl` solution is `520 Omega`, calculate the conductivity and molar conductivity of `0.02 M KCl` solution. The conductivity of `0.1 M KCl `solution is `1.29 S m^(-1)`.

Explanation

To solve the problem, we need to calculate the conductivity and molar conductivity of the `0.02 M KCl` solution using the given data. Let's break it down step by step.

### Step 1: Understand the Given Data
- For the `0.1 M KCl` solution:
- Resistance (R1) = 100 Ω
- Conductivity (κ1) = 1.29 S/m
- For the `0.02 M KCl` solution:
- Resistance (R2) = 520 Ω
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