Calculate the `EMF` of the cell in which the following reaction takes place `:`
`Ni(s)+2Ag^(o+)(0.002M) rarr Ni^(2+)(0.160M)+2Ag(s)`

Explanation

To calculate the EMF of the cell for the given reaction, we can follow these steps:

### Step 1: Write the half-reactions and identify the standard EMF
The overall reaction is:
\[ \text{Ni(s)} + 2 \text{Ag}^+ \rightarrow \text{Ni}^{2+} + 2 \text{Ag(s)} \]

The half-reactions are:
1. Oxidation: \( \text{Ni(s)} \rightarrow \text{Ni}^{2+} + 2e^- \)
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