The cell in which the following reaction occurs
`2Fe^(3+)(aq)+2I^(-)(aq)to2Fe^(2+)(aq)+I_(2)(aq)+I_(2)(s)` has `E_(cell)^(0)=0.236V` at 298 K.
Calculate the standard gibbs energy and the equilibrium constant of the cell reaction.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the Standard Gibbs Energy (ΔG°)

The formula to calculate the standard Gibbs energy change (ΔG°) is given by:

\[
\Delta G^\circ = -nFE^\circ_{\text{cell}}
...