The molar conductivity of `0.25 mol L^(-1)` methanoic acid is `46.1 S cm^(2) mol^(-1)`. Calculate the degree of dissociation constant.
Given `: lambda_((H^(o+)))^(@)=349.6S cm^(2)mol^(-1) ` and
`lambda_(HCOO^(-))^(@)=54.6Scm^(2)mol^(-1)`

Explanation

To find the degree of dissociation (α) of methanoic acid, we can use the following steps:

### Step 1: Understand the given values
- Molar conductivity of methanoic acid (λ_M) = 46.1 S cm² mol⁻¹
- Limiting molar conductivity of H⁺ (λ⁰_H⁺) = 349.6 S cm² mol⁻¹
- Limiting molar conductivity of HCOO⁻ (λ⁰_HCOO⁻) = 54.6 S cm² mol⁻¹

### Step 2: Calculate the limiting molar conductivity (λ⁰_M) of methanoic acid
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