The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M KCl` solution at `298K` is `0.146 xx 10^(-3) S cm^(-1)`.

Explanation

To find the cell constant of a conductivity cell containing a 0.001 M KCl solution at 298 K, we can follow these steps:

### Step 1: Understand the relationship between resistance, conductance, and cell constant
The relationship between resistance (R), conductance (G), and cell constant (L/A) can be expressed as:
\[ G = \frac{1}{R} \]
Where:
- \( G \) is the conductance in S (Siemens),
- \( R \) is the resistance in Ω (Ohms).
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