The conductivity of `0.00241 M` acetic acid is `7.896xx10^(-5)Scm^(-1)`. Calculate its molar conductivity. If `wedge_(m)^(@)` for acetic acid is `390.5Scm^(2)mol^(-1)`, what is its dissociation constant ?

Explanation

To solve the problem step by step, we will first calculate the molar conductivity of acetic acid and then determine its dissociation constant.

### Step 1: Write down the given values
- Molarity of acetic acid (C) = `0.00241 M`
- Conductivity (κ) = `7.896 × 10^(-5) S cm^(-1)`
- Molar conductivity at infinite dilution (ΔM⁰) = `390.5 S cm² mol^(-1)`

### Step 2: Calculate the molar conductivity (ΔM)
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