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Write IUPAC names of the products obtain...

Write IUPAC names of the products obtained by the ozonolysis of the following compounds:
(i) Pent-2-ene (ii) 3,4-Dimethyl-hept-3-ene
(iii) 2-Ethylbut-1-ene (iv) 1-Phenylbut-1-ene

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To solve the problem of determining the IUPAC names of the products obtained by the ozonolysis of the given compounds, we will go through each compound step by step. ### Step 1: Ozonolysis of Pent-2-ene 1. **Identify the structure**: Pent-2-ene has the structure CH3-CH=CH-CH2-CH3. 2. **Ozonolysis reaction**: The double bond between the second and third carbon atoms will break, and ozone will add to form an ozonide intermediate. 3. **Reduction**: The ozonide is then reduced using zinc and water, leading to the formation of two carbonyl compounds. 4. **Products**: The products are: - Ethanal (acetaldehyde) from the terminal carbon. - Propan-2-one (acetone) from the central carbon. 5. **IUPAC Names**: The final products are Ethanal and Propan-2-one. ### Step 2: Ozonolysis of 3,4-Dimethylhept-3-ene 1. **Identify the structure**: 3,4-Dimethylhept-3-ene has the structure CH3-CH(CH3)-C(CH3)=CH-CH2-CH3. 2. **Ozonolysis reaction**: The double bond at the third position will break, forming an ozonide. 3. **Reduction**: The ozonide is reduced to yield two carbonyl compounds. 4. **Products**: The products are: - Butan-2-one from the left side of the double bond. - Pentan-2-one from the right side of the double bond. 5. **IUPAC Names**: The final products are Butan-2-one and Pentan-2-one. ### Step 3: Ozonolysis of 2-Ethylbut-1-ene 1. **Identify the structure**: 2-Ethylbut-1-ene has the structure CH3-CH=CH-CH2-CH3 with an ethyl group on the second carbon. 2. **Ozonolysis reaction**: The double bond will break, forming an ozonide. 3. **Reduction**: The ozonide is reduced to yield two carbonyl compounds. 4. **Products**: The products are: - Methanal (formaldehyde) from the terminal carbon. - Pentan-3-one from the central carbon. 5. **IUPAC Names**: The final products are Methanal and Pentan-3-one. ### Step 4: Ozonolysis of 1-Phenylbut-1-ene 1. **Identify the structure**: 1-Phenylbut-1-ene has the structure C6H5-CH=CH-CH2-CH3. 2. **Ozonolysis reaction**: The double bond will break, forming an ozonide. 3. **Reduction**: The ozonide is reduced to yield two carbonyl compounds. 4. **Products**: The products are: - Benzaldehyde from the phenyl side. - Propan-2-one from the butyl side. 5. **IUPAC Names**: The final products are Benzaldehyde and Propan-2-one. ### Summary of IUPAC Names of Products: - (i) Pent-2-ene → Ethanal and Propan-2-one - (ii) 3,4-Dimethylhept-3-ene → Butan-2-one and Pentan-2-one - (iii) 2-Ethylbut-1-ene → Methanal and Pentan-3-one - (iv) 1-Phenylbut-1-ene → Benzaldehyde and Propan-2-one

To solve the problem of determining the IUPAC names of the products obtained by the ozonolysis of the given compounds, we will go through each compound step by step. ### Step 1: Ozonolysis of Pent-2-ene 1. **Identify the structure**: Pent-2-ene has the structure CH3-CH=CH-CH2-CH3. 2. **Ozonolysis reaction**: The double bond between the second and third carbon atoms will break, and ozone will add to form an ozonide intermediate. 3. **Reduction**: The ozonide is then reduced using zinc and water, leading to the formation of two carbonyl compounds. 4. **Products**: The products are: - Ethanal (acetaldehyde) from the terminal carbon. ...
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