Home
Class 12
CHEMISTRY
Why does R3P=0 exist but R3N=0 does not ...

Why does `R_3P=0` exist but `R_3N=0` does not `(R=` alkyl group)?

Text Solution

Verified by Experts

N (unlike P) lacks the d-orbital. This restricts nitrogen to expand its coordination number beyond four. Hence, `R_(3)N=O` does not exist.
Promotional Banner

Topper's Solved these Questions

  • THE P-BLOCK ELEMENTS

    NCERT ENGLISH|Exercise EXERCISE|74 Videos

  • THE D AND F BLOCK ELEMENTS

    NCERT ENGLISH|Exercise Exercise|38 Videos

  • THE SOLID STATE

    NCERT ENGLISH|Exercise All Questions|49 Videos

Similar Questions

Explore conceptually related problems

(a) Complete the followingh chemical reaction equations : (i) Cu+HNO_(3 (dilute))to (ii) P_4+NaOH+H_2Oto (b) (i) why does R_3P=O exist but R_3N=O does not ? (R=alkyl group) (ii) why is dioxygen a gas but sulphur a solid ? (iii) why are halogens coloured ?

Give reasons for the following : (i) Where R is an alkyl group, R_(3)P=O" exists but "R_(3)N=O does not. (ii) PbCl_(4)" is more covalent than "PbCl_(2). (iii) At room temperature, N_(2) is much less reactive.

CIF_3 exists but FCl_3 does not exist. Why?

Ketones (R-overset(O)overset("||")C-R') can be obtained in one step by (where R and R' are alkyl groups)

(a) Why elemental phosphorous does not exist as P_2 like N_2 ? (b) NCl_3 gets easily hydrolysed, while NF_3 does not. Why ?

A function f:R->R satisfies the relation f((x+y)/3)=1/3|f(x)+f(y)+f(0)| for all x,y in R. If f'(0) exists, prove that f'(x) exists for all x, in R.

Let for A=[(1,0,0),(2,1,0),(3,2,1)] , there be three row matrices R_(1), R_(2) and R_(3) , satifying the relations, R_(1)A=[(1,0,0)], R_(2)A=[(2,3,0)] and R_(3)A=[(2,3,1)] . If B is square matrix of order 3 with rows R_(1), R_(2) and R_(3) in order, then The value of det. (2A^(100) B^(3)-A^(99) B^(4)) is

If vec r_1, vec r_2, vec r_3 are the position vectors of the collinear points and scalar p a n d q exist such that vec r_3=p vec r_1+q vec r_2, then show that p+q=1.

If P_1:vec r.vecn_1-d_1=0 P_2:vec r.vec n_2-d_2=0 and P_3:vec r.vecn_3-d_3=0 are three non-coplanar vectors, then three lines P_1= 0 , P_2=0 ; P_2=0 , P_3=0 ; P_3=0 P_1=0 are

If vec r_1, vec r_2, vec r_3 are the position vectors off thee collinear points and scalar pa n dq exist such that vec r_3=p vec r_1+q vec r_2, then show that p+q=1.