Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.

Explanation

To justify the placement of oxygen (O), sulfur (S), selenium (Se), tellurium (Te), and polonium (Po) in the same group of the periodic table, we can analyze their electronic configuration, oxidation states, and hydride formation. Here’s a step-by-step breakdown:

### Step 1: Electronic Configuration
- **Electronic Configuration of Group 16 Elements**:
- Oxygen (O): Atomic number 8, electronic configuration is \(1s^2 2s^2 2p^4\).
- Sulfur (S): Atomic number 16, electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^4\).
- Selenium (Se): Atomic number 34, electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 4p^4\).
- Tellurium (Te): Atomic number 52, electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 4p^6 5s^2 5p^4\).
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