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How are xenon fluorides XeF(2), XeF(4) a...

How are xenon fluorides `XeF_(2)`, `XeF_(4)` and `XeF_(6)` obtained?

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To obtain xenon fluorides \( \text{XeF}_2 \), \( \text{XeF}_4 \), and \( \text{XeF}_6 \), we can follow these steps: ### Step 1: Formation of \( \text{XeF}_2 \) - **Reaction**: Xenon gas reacts with fluorine gas. - **Chemical Equation**: \[ \text{Xe(g)} + \text{F}_2(g) \rightarrow \text{XeF}_2(s) \] ...
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S_(1): Argon is used in arc welding of metals or alloys to provide an inert atomosphere. S_(2):" XeF_(2),XeF_(4) and XeF_(6) are colourless crystalline solids and sublime readily at 298K . S_(3):XeF_(2),XeF_(4) and XeF_(6) are readily hydrolysed. S_(4): Xenon fluorides react with flourine ion acceptor to form cationic species and fluoride ion donors to form fluoro anions.

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Noble gases have completely filled valance shall i.e. ns^(2)np^(6) exceps He. Noble gases are monoatomic under normal conditions .Law boiling point of the ligher noble gases are due to weak vander walls forces between the atoms and absence of any interatomic interactions Xe reacts with F_(2) so give a source of flouoride mainly XeF_(2),XeF_(4),XeF_(4),XeF_(3) on complete hydrolyses gives XeF_(3) , Oxidation state of Xe in XeF_(2) is