A hydrocarbon `C_(5)H_(10)` does not react with chlorine in dark but gives a single monochloro compound `C_(5)H_(9)Cl` in bright sunlight. Identify the hydrocarbon.

Explanation

To identify the hydrocarbon \( C_5H_{10} \) that does not react with chlorine in the dark but gives a single monochloro compound \( C_5H_9Cl \) in bright sunlight, we can follow these steps:

### Step 1: Analyze the Molecular Formula
The molecular formula \( C_5H_{10} \) indicates that the compound could either be an alkene or a cycloalkane.

**Hint:** Remember that alkenes have a double bond and can react with chlorine in the dark, while cycloalkanes do not have double bonds.

### Step 2: Determine Reactivity with Chlorine
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