Write the isomers of the compound having formula `C_(4)H_(9)Br`.

Explanation

To find the isomers of the compound with the formula C₄H₉Br, we need to consider the different structural arrangements of the carbon atoms and the placement of the bromine atom.

### Step-by-Step Solution:

1. **Identify the Base Structure**:
The molecular formula C₄H₉Br indicates that we have a four-carbon alkane (butane) with a bromine atom attached. The general formula for this type of compound is CₙH₂ₙ₊₁Br, which confirms that we are dealing with a saturated compound (no double or triple bonds).

2. **Draw the Straight-Chain Isomer**:
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