Write reactions of the final alkylation product of aniline with excess of methyl iodide in the presence of sodium carbonate solution.

Explanation

To solve the question regarding the reactions of the final alkylation product of aniline with excess methyl iodide in the presence of sodium carbonate solution, we can break it down into several steps.

### Step 1: Understand the Structure of Aniline
Aniline is an aromatic amine with the formula C6H5NH2. It consists of a benzene ring (C6H5) attached to an amino group (NH2).

### Step 2: First Alkylation Reaction
When aniline reacts with excess methyl iodide (CH3I), the amino group (NH2) acts as a nucleophile and attacks the methyl group from CH3I. This leads to the substitution of one hydrogen atom on the nitrogen with a methyl group.

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