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An air bubble of volume 1.0 cm^(3) rises...

An air bubble of volume `1.0 cm^(3)` rises from the bottom of a lake 40 m deep at a temperature of `12^(@) C`. To what volume does it grow when it reaches the surface, which is at a temperature of `35^(@) C`. ? Given `1 atm = 1.01 xx 10^(5) Pa`.

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To solve the problem step by step, we will use the combined gas law, which relates the pressure, volume, and temperature of a gas. The formula we will use is: \[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \] ### Step 1: Identify the given values - Initial volume of the bubble, \( V_1 = 1.0 \, \text{cm}^3 \) ...
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