A long solenoid with 15 turns per cm has small loop of area `2.0 cm^(2)` placed inside, normal to the axis of the soleniod. If current carried by the solenoid changes steadily from 2 A to 4 A in 0.1 s, what is the induced voltage in the loop, while the current is changing ?

Explanation

To solve the problem step by step, we will follow the principles of electromagnetic induction and use the relevant formulas.

### Step 1: Identify the Given Data
- Number of turns per cm of the solenoid: \( n = 15 \, \text{turns/cm} \)
- Area of the small loop: \( A = 2.0 \, \text{cm}^2 \)
- Initial current: \( I_1 = 2 \, \text{A} \)
- Final current: \( I_2 = 4 \, \text{A} \)
- Time interval: \( \Delta t = 0.1 \, \text{s} \)
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