Suppose a pure Si-crystal has `5xx10^(28) "atoms" m^(-3)`. It is doped by 1 ppm concentration of pentavalent As. Calculate the number of electrons and holes. Give that `n_(i)=1.5xx10^(16)m^(-3)`.

Explanation

To solve the problem, we need to calculate the number of electrons and holes in a silicon crystal that has been doped with a pentavalent element (arsenic) at a concentration of 1 ppm. We are given the intrinsic carrier concentration \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \) and the number of silicon atoms in the crystal.

### Step-by-Step Solution:

1. **Identify the number of silicon atoms**:
The number of silicon atoms in the crystal is given as:
\[
N_{Si} = 5 \times 10^{28} \, \text{atoms/m}^3
...