The number of silicon atoms per `m^(3) is 5xx10^(28)`. This is doped simultaneously with `5xx10^(22)` atoms per `m^(3)` of Arsenic and `5xx10^(20) per m^(3)` atoms of indium. Calculate the number of electrons and holes. Given that `n_(i)=1.5xx10^(16)m^(-3)`. Is the material n-type or p-type?

Explanation

To solve the problem, we need to calculate the number of electrons (n_e) and holes (n_h) in the doped silicon and determine if the material is n-type or p-type.

### Step 1: Identify the given values
- Number of silicon atoms, \( N_{Si} = 5 \times 10^{28} \, m^{-3} \)
- Number of arsenic atoms (donors), \( N_{As} = 5 \times 10^{22} \, m^{-3} \)
- Number of indium atoms (acceptors), \( N_{In} = 5 \times 10^{20} \, m^{-3} \)
- Intrinsic carrier concentration, \( n_i = 1.5 \times 10^{16} \, m^{-3} \)

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