A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observe on screen 1 m away. It is observed that the first minimum is at a distance of `2.5 mm` from the centre of the screen. Find the width of the slit.

Explanation

To find the width of the slit (denoted as \( d \)), we can use the formula for the position of the minima in a single-slit diffraction pattern. The position of the first minimum is given by:

\[ x = \frac{n \cdot \lambda \cdot D}{d} \]

Where:
- \( x \) is the distance from the center to the first minimum,
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