In a ballistics demonstration, a police officer fires a bullet mass `50.0g` with speed `200ms^(-1)` on soft plywood of thickness 2.00cm. The bullet emerges only with `10%` of its initial kinetic energy. What is the emergent speed of the bullet ?

Explanation

To solve the problem step by step, we will follow the principles of kinetic energy and the information given in the question.

### Step 1: Calculate the initial kinetic energy of the bullet.
The formula for kinetic energy (KE) is given by:

\[ KE = \frac{1}{2} m u^2 \]
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