Suppose while sitting in a parked car, you notice a jogger approaching towards you in the rear view mirror of `R = 2 m`. If the jogger is running at a speed of `5 ms^-1`, how fast is the image of the jogger moving, when the jogger is
(a) 39 m
(b) 29 m
19 m and
(d) 9 m. away ?

Explanation

To solve the problem, we need to find the speed of the image of a jogger moving towards a parked car as observed in a convex rear-view mirror. The jogger runs at a speed of \(5 \, \text{m/s}\), and we will calculate the speed of the image for different distances of the jogger from the mirror.

### Given:
- Radius of curvature of the mirror, \(R = 2 \, \text{m}\)
- Speed of the jogger (object), \(v_o = 5 \, \text{m/s}\)
- Focal length of the mirror, \(f = \frac{R}{2} = 1 \, \text{m}\)

### Mirror Formula:
...