An object of size `3.0 cm` is placed `14 cm` in front of a concave lens of focal length `21 cm`. Describe the image produced by the lens. What happens if the object is moved further from the lens ?

Explanation

To solve the problem step by step, we will use the lens formula and magnification formula to find the characteristics of the image produced by the concave lens.

### Step 1: Identify the given values
- Size of the object (height, h) = 3.0 cm
- Object distance (u) = -14 cm (the negative sign indicates that the object is placed in front of the lens)
- Focal length of the concave lens (f) = -21 cm (the negative sign indicates that it is a concave lens)

### Step 2: Use the lens formula
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