A person with a normal near point `(25 cm)` using a compound microscope with an objective of focal length `8.0 mm` and eye piece of focal length `2.5 cm` can bring an object placed `9.0 cm` from the objective in sharp focus. What is the separation between the two lenses ? Calculate the magnifying power of the microscope ?

Explanation

To solve the problem step by step, we will first gather the necessary information and then apply the lens formula and magnification formulas.

### Given Data:
- Focal length of the objective lens, \( f_0 = 8.0 \, \text{mm} = 0.8 \, \text{cm} \)
- Focal length of the eyepiece lens, \( f_e = 2.5 \, \text{cm} \)
- Object distance from the objective lens, \( u_0 = -9.0 \, \text{cm} \) (negative as per sign convention)
- Normal near point of the person, \( D = 25 \, \text{cm} \)

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