A bullet of mass 0.04 kg moving with a speed of `90 ms^(-1)` enters a heavy wooden block and is stooped after a distance of 60 cm . What is the average resistive force exerted by the block on the bullet ?

Explanation

To solve the problem of finding the average resistive force exerted by the block on the bullet, we can follow these steps:

### Step 1: Identify the given data
- Mass of the bullet (m) = 0.04 kg
- Initial velocity of the bullet (u) = 90 m/s
- Final velocity of the bullet (v) = 0 m/s (since it comes to rest)
- Distance traveled in the block (s) = 60 cm = 0.6 m (convert to meters)

...