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A mass of 6 kg is suspended by a rope of...

A mass of 6 kg is suspended by a rope of length 2 m from the ceilling A force of 50 N in the horizontal direction is applied at the mid - point P of the rope as shown . What is the angle the rope makes with the vertical in equilibrium ? (Take = `10 ms^(-2)`) . Neglect mass of the rope .

Text Solution

AI Generated Solution

To solve the problem, we will analyze the forces acting on the mass and the rope. Here's a step-by-step solution: ### Step 1: Identify the Forces Acting on the Mass The mass of 6 kg creates a gravitational force acting downward, which can be calculated as: \[ F_g = m \cdot g \] Where: ...
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A mass of 3kg is suspended by a rope of length 2m from the ceiling. A force of 40N in the' horizontal direction is applied at midpoint P of the rope as shown. What is the angle the rope makes with the vertical in equilibrium and the tension in part of string attached to the ceiling ? (Neglect the mass of the rope, g = 10m//s^2 )

A mass of 6 kg is suspended by a rope of length 2m from a celling. A force of 50N is applied in horizontal direction at the mid point of the rope. What is the angle of the rope with the verticle in equilibrium:-

Knowledge Check

  • A block fof mass 5kg is suspended by a massless rope of length 2 m from the ceilling. A force of 50 N is applied in the horizontal direction at the midpoint P of the rope, as shown in the figure. The angle made by the rope with the vertical in equilibrium is (Take g=10ms^(-2)m .

    A
    `30^(@)`
    B
    `40^(@)`
    C
    `60^(@)`
    D
    `45^(@)`

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