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A 70kg man stands in contact against the...

A `70kg` man stands in contact against the inner wall of a hollow cylindrical drum of radius `3m` rotating about its vertical axis. The coefficient of friction between the wall and his clothing is `0.15`. What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed?

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To solve the problem, we need to determine the minimum rotational speed (angular velocity, \(\omega\)) of a hollow cylindrical drum that allows a 70 kg man to remain stuck against the wall when the floor is suddenly removed. ### Step-by-Step Solution: 1. **Identify Forces Acting on the Man:** - The weight of the man (\(W\)) acts downward: \[ W = mg ...
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A 70kg man stands in contact against the inner wall of a hollw cylindrical drum of radius 3m rotating about its verticle axis. The coefficient of friction between the wall and his clothing nis 0.15 . What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed?

A 70 kg man stands in contact against the wall of a cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min. The coefficient of friction between the wall and his clothing is 0.15. What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed ?

A person stands in contact against a wall of cylindrical drum of radius r, rotating with an angular velocity omega . If mu is the coefficient of friction between the wall and the person, the minimum rotational speed which enables the person to remain stuck to the wall is

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A block of mass 10 kg in contact against the inner wall of a hollow cylindrical drum of radius 1m. The coefficient of friction between the block and the inner wall of the cylinder is 0.1. The minimum angular velocity needed for the cylinder to keep the block stationary when the cylinder is vertical and rotating about its axis, will be (g=10 m//s^(2))

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A small bead of mass m = 1 kg is free to move on a circular hoop. The circular hoop has centre at C and radius r = 1 m and it rotates about a fixed vertical axis. The coefficient of friction between bead and hoop is mu=0.5 . The maximum angular speed of the hoop for which the bead does not have relative motion with respect to hoop, at the position shown in figure is : (Take g = 10 m//s^(2) )

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NCERT ENGLISH-LAWS OF MOTION -EXERCISE
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  14. Two bodies A and B of mass 5 kg and 10 kg contact with each other rest...

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  15. A block of mass 15 kg is placed on a long trolley . The coefficient of...

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  16. The rear side of a truck is open and a box of 40 kg mass is placed 5 m...

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  18. You may have seen in a circus a motorcyclist driving in vertical loops...

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  19. A 70kg man stands in contact against the inner wall of a hollow cylind...

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  20. A thin circular wire of radius R rotates about its vertical diameter w...

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