the threashold frequency `v_(0)` for a metal is `7xx10^(14)s^(-1)` . Calculate the kinetic energy of an electron emitted when radiation of fequency `v = 1.0 xx 10^(15)s^(-1)` hits the metal .

Explanation

To solve the problem, we will use the formula derived from the photoelectric effect, which states that the kinetic energy (KE) of the emitted electron can be calculated using the equation:

\[ KE = h \nu - h \nu_0 \]

Where:
- \( KE \) is the kinetic energy of the emitted electron.
- \( h \) is Planck's constant, approximately \( 6.626 \times 10^{-34} \, \text{J s} \).
- \( \nu \) is the frequency of the incident radiation.
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