Electromagnetic radiation of wavelength `242` nm is just sufficient to ionise a sodium atom. Calculate the energy corresponding to this wavelength and the ionisation potential of Na.

Explanation

To solve the problem of calculating the energy corresponding to the wavelength of 242 nm and the ionization potential of sodium (Na), we will follow these steps:

### Step 1: Understand the relationship between energy and wavelength
The energy (E) of electromagnetic radiation can be calculated using the formula:
\[ E = \frac{hc}{\lambda} \]
where:
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J s} \)),
- \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)),
...