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Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength ` 6800` Å . Calculate threshold frequency `( v_0)` and work function `(W_0)` of the metal.

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To solve the problem of calculating the threshold frequency \( v_0 \) and the work function \( W_0 \) of the metal when electrons are emitted with zero velocity from a metal surface exposed to radiation of wavelength \( 6800 \) Å, we will follow these steps: ### Step 1: Convert Wavelength to Meters The given wavelength is in angstroms, and we need to convert it to meters for our calculations. \[ \text{Wavelength} (\lambda) = 6800 \, \text{Å} = 6800 \times 10^{-10} \, \text{m} \] ...
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A monochromatic light soure of frequency f illuminates a metallic surface and ejects photoelectrons. The photoelectrons having maximum energy are just able to ionize the hydrogen atoms in ground state. When the whole experiment is repeated with an incident radiation of frequency (5)/(6) f , the photoelectrons so emitted are able to excite the hydrogen atom beam which then emits a radiation of wavelength 1215 Å . (a) What is the frequency of radiation? (b) Find the work- function of the metal.

Calculate the threshold freqency of the metal from the photoelectrons are emitted with zero velocity when exposed to radiation of wavelength 6800 Å Hint : KE = (1)/(2) mv^(2) hv= hv_(0) + KE, KE=0 v= (c ) /( lambda)

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The emission of electrons from a metal surface exposed rto light radaition of appropriate wavelength is called photoelectroic effect .The emmited electron are called photo=-weklectron work function of threshold energy may be defined as the minimum amount of energy required to ejercted electron from a most surface .According to Einstein Maximum kinetic energy of ejected electron = Aborbed energy - Work function (1)/(2) mv_(max)^(2) = h(v) - h(v_(n)) = hv [(1)/(lambda) -0 (1)/(lambda_(n))] Where v_(n) and lambda_(0) are thereshold frequency and threshold wavelength respectively Sopping potential : it is the miximum potential at which the photoelectric current becomes zero if V_(0) is the stopping potential eV_(0) = h(v- v_(0)) Whaich of the following is the graph between the frequency (V) of the incident radiation and the stopping potential (v) ?

The emission of electrons from a metal surface exposed rto light radaition of appropriate wavelength is called photoelectroic effect .The emmited electron are called photo=-weklectron work function of threshold energy may be defined as the minimum amount of energy required to ejercted electron from a most surface .According to Einstein Maximum kinetic energy of ejected electron = Aborbed energy - Work function (1)/(2) mv_(max)^(2) = h(v) - h(v_(n)) = hv [(1)/(lambda) -0 (1)/(lambda_(n))] Where v_(n) and lambda_(0) are thereshold frequency and threshold wavelength respectively Sopping potential : it is the miximum potential at which the photoelectric current becomes zero if V_(0) is the stopping potential eV_(0) = h(v- v_(0)) The stopping potential as a function on electron frtequency is plotted for two photoelectric surface A abd B The graph show that the work function of A is

The kinetic energy of the most energetic photoelectrons emitted from a metal surface is doubled when the wavelength of the incident radiation is reduced from lamda_1 " to " lamda_2 The work function of the metal is

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