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Explain , giving reason , which of the f...

Explain , giving reason , which of the following sets of quantum number are not possible `{:(a,n= 0 ,l = 0, m_(1) = 0, m_(s) = +1//2),(b,n= 1 ,l = 0, m_(1) = 0, m_(s) = -1//2),(c,n= 1 ,l = 1, m_(1) = 0, m_(s) = +1//2),(d,n= 2 ,l = 1, m_(1) = 0, m_(s) = -1//2),(e,n= 3 ,l = 3, m_(1) = -3, m_(s) = +1//2),(f,n= 3 ,l = 1, m_(1) = 0, m_(s) = +1//2):}`

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To determine which sets of quantum numbers are not possible, we need to understand the rules governing quantum numbers: 1. **Principal Quantum Number (n)**: This can take any positive integer value (n = 1, 2, 3,...). It cannot be zero. 2. **Azimuthal Quantum Number (l)**: This can take integer values from 0 to (n-1). Therefore, l must always be less than n. 3. **Magnetic Quantum Number (ml)**: This can take integer values from -l to +l, including zero. 4. **Spin Quantum Number (ms)**: This can only take two values: +1/2 or -1/2. Now, let's analyze each set of quantum numbers provided in the question: ...
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Explain giving reasons, which of the following sets of quantum numbers are not possible? (a) n=0, l=0, m_(l)=0, m_(s)=+1/2 (b) n=1, l=0, m_(l)=0, m_(s)=-1/2 (c) n=1, l=1, m_(l)=0, m_(s)=+1/2 (d) n=2, l=1, m_(l)=0, m_(s)=-1/2 (e) n=3, l=3, m_(l)=-3, m_(s)=+1/2 (f) n=3, l=1, m_(l)=0, m_(s)=+1/2

From the following sets of quantum numbers , state which are possible ? (i) n=0,l=0,m_(l)=1,m_(s)= +1//2 (ii) n=2,l=1,m_(l)=0,m_(s) = -1//2 (iii) n=2, l=0,m_(1)=3,m_(s) = +1//2 (iv) n=3,l=1,m_(l)=0,m_(s) = +1//2

Which of the following sets of quantum numbers represents the highest energy of an electron? (A) n = 5, l = 0, m = 0, s = +1/2 (B) n = 6, l = 2, m = 1, s = +1/2 (C) n = 5, l = 1, m = 1, s = -1/2 (D) n = 4, l = 1, m = 0 s = -1/2

The quantum number of electrons are given below: Arrange then in order of increasing energies a. n= 4,l= 2,m_(1)= -2, m_(s)= -(1)/(2) b. n= 3,l= 2,m_(1) = 1, m_(s)= +(1)/(2) c. n= 4,l= 1,m_(1) = 0, m_(s)= +(1)/(2) e.n= 3,l= 2,m_(1)= -2, m_(s)= +(1)/(2) f. n= 4,l= 1,m_(1) = +1, m_(s)= +(1)/(2)

From the following sets quantum number state which are possible. Explain why the other are not permitted ? a. n = 0, l = 0, m= 0, s = + 1//2 b. n = 1, l = 0, m= 0, s = - 1//2 c. n = 1, l = 1, m= 0, s = + 1//2 d. n = 1, l = 0, m= +1, s = + 1//2 e. n = 0, l = 1, m= -1, s = - 1//2 f. n = 2, l = 2, m= 0, s = - 1//2 g. n = 2, l = 1, m= 0, s = - 1//2

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists: 1. n=4 , l=2 , m_(i) =-2, m_(s) =-1//2 2. n=3 , l=2 , m_(l) =1 , m_(s) =+1//2 3. n=4 , l=2 ,m_(l)=-2, m_(s) =-1//2 4. n=3 , l= 2, m_(i) =-1 , m_(s) = +1//2 5. n=3 , l=1 , m_(l) =-1 , m_(s) = +1//2 6. n=4 , l= 1 , m_(l) =0 , m_(s) =+1//2

Which of the following sets of quantum numbers do not belong to 2p subshell? (i) n=2, l=1, m=+1, s=+1/2 (ii) n=2, l=0, m=0, s=-1/2 (iii) n=1, l=1, m=0, s=+1/2

Designate the electrons having the following sets of quantum numbers, (a) n=2, l=0, m =0, s=+1/2 (b) n=3, l=1, m=+1, s=+1/2 (c ) n=l, l=0, m=0, s=-1/2

Designate the electrons with the following sets of quantum numbers : (a) n=3, l=0, m=0, s=-1/2 (b) n=2, l=1, m=+1, s=+1/2 (c ) n=5, l=0, m=0, s=+1/2

The decrerasing order of energy for the electrons represented by the following sets of quantum number is : 1. n = 4,l = 0,m = 0,s = +- 1//2 2. n = 3,l = 1,m = 1,s = - 1//2 3. n = 3,l = 2,m = 0,s = + 1//2 4. n = 3,l = 0,m = 0,s = - 1//2

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