If the position of the electron is measured within an accuracy of `+- 0.002 nm`. Calculate the uncertainty in the momentum of the electron. Suppose the momentum of the electron is `h//4pi_(m)xx0.05 nm`, is there any problem in defining this value.

Explanation

To solve the problem, we will use the Heisenberg Uncertainty Principle, which states that the product of the uncertainties in position (Δx) and momentum (Δp) of a particle is a constant:

\[ \Delta x \cdot \Delta p \geq \frac{h}{4\pi} \]

Where:
- \( \Delta x \) is the uncertainty in position,
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