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The quantum numbers of six electrons are...

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists:
` 1. n=4 , l=2 , m_(i) =-2, m_(s) =-1//2 `
`2. n=3 , l=2 , m_(l) =1 , m_(s) =+1//2`
3.`n=4 , l=2 ,m_(l)=-2, m_(s) =-1//2`
4. ` n=3 , l= 2, m_(i) =-1 , m_(s) = +1//2`
5. ` n=3 , l=1 , m_(l) =-1 , m_(s) = +1//2`
6. `n=4 , l= 1 , m_(l) =0 , m_(s) =+1//2`

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To solve the problem of arranging the given quantum numbers in order of increasing energies, we will follow these steps: ### Step 1: Identify the Principal Quantum Number (n) and Azimuthal Quantum Number (l) The energy of an electron in an atom primarily depends on the principal quantum number (n) and the azimuthal quantum number (l). The general order of energy levels is determined by the values of n and l. The energy increases with increasing n, and for the same n, it increases with increasing l. ### Step 2: List the Given Quantum Numbers We have the following quantum numbers for the six electrons: 1. (n=4, l=2, m_i=-2, m_s=-1/2) ...
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The quantum number of electrons are given below: Arrange then in order of increasing energies a. n= 4,l= 2,m_(1)= -2, m_(s)= -(1)/(2) b. n= 3,l= 2,m_(1) = 1, m_(s)= +(1)/(2) c. n= 4,l= 1,m_(1) = 0, m_(s)= +(1)/(2) e.n= 3,l= 2,m_(1)= -2, m_(s)= +(1)/(2) f. n= 4,l= 1,m_(1) = +1, m_(s)= +(1)/(2)

Explain giving reasons, which of the following sets of quantum numbers are not possible? (a) n=0, l=0, m_(l)=0, m_(s)=+1/2 (b) n=1, l=0, m_(l)=0, m_(s)=-1/2 (c) n=1, l=1, m_(l)=0, m_(s)=+1/2 (d) n=2, l=1, m_(l)=0, m_(s)=-1/2 (e) n=3, l=3, m_(l)=-3, m_(s)=+1/2 (f) n=3, l=1, m_(l)=0, m_(s)=+1/2

Explain , giving reason , which of the following sets of quantum number are not possible {:(a,n= 0 ,l = 0, m_(1) = 0, m_(s) = +1//2),(b,n= 1 ,l = 0, m_(1) = 0, m_(s) = -1//2),(c,n= 1 ,l = 1, m_(1) = 0, m_(s) = +1//2),(d,n= 2 ,l = 1, m_(1) = 0, m_(s) = -1//2),(e,n= 3 ,l = 3, m_(1) = -3, m_(s) = +1//2),(f,n= 3 ,l = 1, m_(1) = 0, m_(s) = +1//2):}

The quantum number of four electrons are given below: n=4,l=2,m_(l)=-2,m_(s)=-1//2 n=3,l=2,m_(l),m_(s)=+1//2 n=4,l=1,m_(l)=0,m_(s)=+1//2 n=3,l=1,m_(l)=1,m_(s)=-1//2 The correct order of their increasing energies will be:

From the following sets of quantum numbers , state which are possible ? (i) n=0,l=0,m_(l)=1,m_(s)= +1//2 (ii) n=2,l=1,m_(l)=0,m_(s) = -1//2 (iii) n=2, l=0,m_(1)=3,m_(s) = +1//2 (iv) n=3,l=1,m_(l)=0,m_(s) = +1//2

From the following sets quantum number state which are possible. Explain why the other are not permitted ? a. n = 0, l = 0, m= 0, s = + 1//2 b. n = 1, l = 0, m= 0, s = - 1//2 c. n = 1, l = 1, m= 0, s = + 1//2 d. n = 1, l = 0, m= +1, s = + 1//2 e. n = 0, l = 1, m= -1, s = - 1//2 f. n = 2, l = 2, m= 0, s = - 1//2 g. n = 2, l = 1, m= 0, s = - 1//2

The decrerasing order of energy for the electrons represented by the following sets of quantum number is : 1. n = 4,l = 0,m = 0,s = +- 1//2 2. n = 3,l = 1,m = 1,s = - 1//2 3. n = 3,l = 2,m = 0,s = + 1//2 4. n = 3,l = 0,m = 0,s = - 1//2

Arrange the electrons represented by the following sets of quantum numbers in decreasing order of energy. (i) n=4, l=0, m_(l)=0, s=+1//2 , (ii) n=3, l=1, m_(l)=1, s=-1//2 (iii) n=3, l=2, m_(l)=0, s=+1//2 , (iv) n=3, l=0, m_(l)=0, s=-1//2

Which of the following sets of quantum numbers represents the highest energy of an electron? (A) n = 5, l = 0, m = 0, s = +1/2 (B) n = 6, l = 2, m = 1, s = +1/2 (C) n = 5, l = 1, m = 1, s = -1/2 (D) n = 4, l = 1, m = 0 s = -1/2

The quantum number of four electrons are given below: I. n=4,l=2,m_l=-2,m_s=-1/2 II. n=3,l=2,m_l=1,m_s=+1/2 III. n = 4 , l =1 ,m _l=0 ,m_s=+1/2 IV. n=3,l=1,m_l=1,m_s=-1/2 The correct order of their increasing energies will be

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