The unpaired electrons in `Al` and `Si` are present in `3p` orbital. Which electrons will experience more effective nuclear charge from the nucleus?

Explanation

To determine which unpaired electrons in aluminum (Al) and silicon (Si) experience more effective nuclear charge, we can follow these steps:

### Step 1: Determine the Electronic Configurations
- **Aluminum (Al)** has an atomic number of 13. Its electronic configuration is:
\[ \text{Al: } 1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^1 \]
- **Silicon (Si)** has an atomic number of 14. Its electronic configuration is:
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