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45 g of ethylene glycol C(2)H(6)O(2) is ...

`45 g` of ethylene glycol `C_(2)H_(6)O_(2)` is mixed with `600 g` of water. Calculate (a) the freezing point depression and (b) the freezing point of solution.
Given`K_(f)=1.86 K kg mol^(-1)`.

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To solve the problem, we will follow these steps: ### Step 1: Calculate the number of moles of ethylene glycol (C₂H₆O₂) First, we need to find the molecular weight of ethylene glycol: - The molecular formula of ethylene glycol is C₂H₆O₂. - The molecular weight can be calculated as follows: - Carbon (C): 12.01 g/mol × 2 = 24.02 g/mol ...
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