`200 cm^(3)` of an aqueous solution of a protein contains `1.26 g `of the protein. The osmotic pressure of such a solution at `300 K` is found to be `2.57 xx10^(-3)` bar. Calculate the molar mass of the protein.

Explanation

To calculate the molar mass of the protein from the given data, we can follow these steps:

### Step 1: Understand the given data
- Volume of the solution (V) = 200 cm³ = 200 mL = 0.200 L (since 1 L = 1000 mL)
- Mass of the protein (m) = 1.26 g
- Osmotic pressure (π) = 2.57 × 10^(-3) bar
- Temperature (T) = 300 K
- Gas constant (R) = 0.08314 L·bar/(K·mol)
...