Two grams of benzoic acid `(C_(6)H_(5)COOH)` dissolved in `25.0 g` of benzene shows a depression in freezing point equal to `1.62 K`. Molal depression constant for benzene is `4.9 K kg^(-1)"mol^-1`. What is the percentage association of acid if it forms dimer in solution?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Gather Given Data
- Mass of benzoic acid (C₆H₅COOH), \( W_B = 2 \, \text{g} \)
- Mass of benzene (solvent), \( W_A = 25 \, \text{g} \)
- Depression in freezing point, \( \Delta T_F = 1.62 \, \text{K} \)
- Molal depression constant for benzene, \( K_F = 4.9 \, \text{K kg}^{-1} \text{mol}^{-1} \)

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