The vapour pressure of pure liquids `A` and `B` is 450 and `700mm Hg`, respectively, at `350K. ` Find out the composition of the liquid mixture if the total vapour pressure is `600mm Hg`. Also find the composition of the vapour phase.

Explanation

To solve the problem, we will use Raoult's law, which states that the vapor pressure of a component in a mixture is equal to the vapor pressure of the pure component multiplied by its mole fraction in the liquid phase.

### Step-by-Step Solution:

1. **Identify Given Data:**
- Vapor pressure of pure liquid A, \( P^0_A = 450 \, \text{mm Hg} \)
- Vapor pressure of pure liquid B, \( P^0_B = 700 \, \text{mm Hg} \)
- Total vapor pressure, \( P_T = 600 \, \text{mm Hg} \)
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