Vapour pressure of pure water at `298 K ` is `23.8 mm Hg`. `50g` of urea `(NH_(2)CONH_(2))` is dissolved in `850g` of water. Calculate the vapour pressure of water for this solution and its relative lowering.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the number of moles of urea (NH₂CONH₂)
The molecular weight of urea is 60 g/mol. We have 50 g of urea.

\[ \text{Moles of urea} (N_2) = \frac{\text{mass}}{\text{molar mass}} = \frac{50 \, \text{g}}{60 \, \text{g/mol}} = 0.8333 \, \text{mol} \]
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