Volume of `0.1M HCl` required to react completely with 1g equimolar mixture of `Na_(2)CO_(3)` and `NaHCO_(3)` is

Explanation

To find the volume of 0.1 M HCl required to react completely with a 1 g equimolar mixture of Na₂CO₃ and NaHCO₃, we can follow these steps:

### Step 1: Determine the mass of each component in the mixture
Since the mixture is equimolar, we can assume that the mass of Na₂CO₃ is X grams and the mass of NaHCO₃ is (1 - X) grams. The total mass is 1 g, so:
\[ X + (1 - X) = 1 \]

### Step 2: Calculate the moles of Na₂CO₃ and NaHCO₃
The molar masses are:
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