An aqueous solution of `2` per cent `(wt.//wt)` non-volatile solute exerts a pressure of `1.004` bar at the boiling point of the solvent. What is the molecular mass of the solute?

Explanation

To find the molecular mass of the non-volatile solute in the given aqueous solution, we can use Raoult's Law. Here is a step-by-step solution:

### Step 1: Identify Given Values
- The solution is a 2% (wt/wt) solution of a non-volatile solute.
- The vapor pressure of the solution (P1) is 1.004 bar.
- The vapor pressure of pure water (P1°) at boiling point is 1.013 bar.

### Step 2: Calculate the Relative Lowering of Vapor Pressure
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