Heptane and octane form ideal solution. At `373K`, the vapour pressure of the two liquids are `105.2 kPa` and `46.8 kPa` respectively. What will be the vapour pressure, in bar, of a mixture of `25g` of heptane and `35g` of octane?

Explanation

To solve the problem of finding the vapor pressure of a mixture of heptane and octane, we will use Raoult's Law. Here’s a step-by-step solution:

### Step 1: Calculate the number of moles of heptane and octane.

1. **Heptane (C7H16)**:
- Given mass = 25 g
- Molar mass of heptane = 100 g/mol
- Number of moles of heptane (n_H) = mass / molar mass = 25 g / 100 g/mol = 0.25 moles
...