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A 5% solution (by mass) of cane sugar in...

A `5%` solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K.

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To solve the problem of finding the freezing point of a 5% glucose solution in water, we will follow these steps: ### Step 1: Understand the Given Data We know: - Freezing point of pure water (Tf°) = 273.15 K - Freezing point of 5% cane sugar solution (Tf) = 271 K - Mass percentage of cane sugar = 5% - Mass percentage of glucose = 5% ...
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(a) A 10% solution (by mass) of sucrose in water has freezing point of 269.15K. Calculate the freezing point of 10% glucose in water, if the freezing point of pure water is 273.15K. Given: (molar mass of sucrose=342 g mol^(-1) ) (Mola mass of glucose =180g mol^(-1) ) (b) Define the following terms: (i) Molality (m) (ii) Abnormal molar mass

A 10% solution (by mass) of sucrose in water has freezing point of 269.15 K. Calculate freezing point of 10% glucose in water, if freezing point of pure is 273.15 K (Given molar mass of sucrose= 342 g mol^(-1) , Molar mass of glucose =180 g mol^(-1) ).

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